Calculus: Early Transcendentals, 8th Edition

Calculus: Early Transcendentals, 8th Edition

Authors: James Stewart

ISBN-13: 978-1285741550

See our solution for Question 9E from Chapter 2.1 from Stewart's Calculus, 8th Edition.

Problem 9E

Chapter:
Problem:
The point P(1, 0) lies on the curve y − sin(10 Pi/x)...

Step-by-Step Solution

Step 1
The slope of a secant line joining P($x_1,y_1$) and Q($x_2,y_2$ is given by:\[{\rm{Slope}} = \dfrac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}\]

Step 2: (a)
Consider the Table of points along with calculated Slopes:

https://imgur.com/nFvNoUS

The slopes do not appear to approach a limit

Step 3: Graph of the Function
Consider the graph of the function given below. As we can see that slopes of the secant lines are not close to each other as it fluctuates largely even for small change in x

https://imgur.com/1BVUxlx

Step 4: c
To find the slope of tangent line, choose point Q very close to P. Let Q be at x=1.00001
\[y\left( {0.00001} \right) = - 0.000314153\]The point Q is: \[Q = \left( {1.00001,- 0.000314153} \right)\]So the slope at P is: \[\begin{array}{l}{S_P} = \dfrac{{0 - \left( { - 0.000314153} \right)}}{{0.00001}}\\ = 31.4153\end{array}\]https://imgur.com/tTLP2YRTherefore,
\[{S_P} = 31.4153\]